CBSE Class 10 Mathematics — Previous Year Questions 2026
Basic + Standard Mathematics | Chapterwise PYQ Collection
1. Class Marks & Median Class
The class mark of the median class of the following data is:
| Class Interval | 10 – 25 | 25 – 40 | 40 – 55 | 55 – 70 | 70 – 85 | 85 – 100 |
|---|---|---|---|---|---|---|
| Frequency | 2 | 3 | 7 | 6 | 6 | 6 |
2. Modal Class Limits
The lower limit of the modal class of the following distribution is:
| Runs Scored | 3000 – 4000 | 4000 – 5000 | 5000 – 6000 | 6000 – 7000 |
|---|---|---|---|---|
| Number of Batsmen | 5 | 10 | 9 | 8 |
The lower limit of the modal class for the following distribution is:
| Marks | 0 – 10 | 10 – 20 | 20 – 30 | 30 – 40 | 40 – 50 |
|---|---|---|---|---|---|
| Number of Students | 5 | 3 | 4 | 8 | 3 |
4. Mode Formula Definitions
In the formula of mode given by \[ \text{Mode} = l+ \left( \frac{f_1-f_0} {2f_1-f_0-f_2} \right)\times h, \] \(f_1\) denotes the:
5. Empirical Relationship
For a distribution, if \(\text{mean}=\text{median}=a\), then its mode is:
For a distribution, if mean = 15 and mode = 12, then its median is:
7. Mean Calculation
Find the mean lifetime (in hours) of the electrical components:
| Lifetime (in hours) | Number of electrical components |
|---|---|
| 0 – 20 | 10 |
| 20 – 40 | 35 |
| 40 – 60 | 50 |
| 60 – 80 | 60 |
| 80 – 100 | 30 |
| 100 – 120 | 15 |
8. Median Calculation
Find the median age of the policy holders:
| Age (in years) | Number of policy holders |
|---|---|
| 15 – 20 | 2 |
| 20 – 25 | 4 |
| 25 – 30 | 18 |
| 30 – 35 | 21 |
| 35 – 40 | 33 |
| 40 – 45 | 11 |
| 45 – 50 | 3 |
| 50 – 55 | 6 |
| 55 – 60 | 2 |
Find the median length (in mm) of the leaves:
| Length in (mm) | Number of leaves |
|---|---|
| 100 – 120 | 8 |
| 120 – 140 | 9 |
| 140 – 160 | 12 |
| 160 – 180 | 5 |
| 180 – 200 | 6 |
10. Missing Frequencies
If the mean number of days a student was absent is 12, find the values of \(x\) and \(y\):
| Number of days | 0 – 4 | 4 – 8 | 8 – 12 | 12 – 16 | 16 – 20 | 20 – 24 |
|---|---|---|---|---|---|---|
| Number of Absent students | 1 | 8 | \(x\) | 6 | 5 | \(y\) |
The mean pocket allowance is ₹180. Find the value of \(f\). Hence find the mode of given data:
| Weekly Pocket Allowance (in ₹) | Number of Children |
|---|---|
| 110 – 130 | 7 |
| 130 – 150 | 6 |
| 150 – 170 | 9 |
| 170 – 190 | 13 |
| 190 – 210 | \(f\) |
| 210 – 230 | 5 |
| 230 – 250 | 4 |
Find the value of \(x\). Hence find the mean daily expenditure:
| Daily Expenditure (in ₹) | Number of Households |
|---|---|
| 500 – 750 | 4 |
| 750 – 1000 | \(2x+1\) |
| 1000 – 1250 | 12 |
| 1250 – 1500 | \(x\) |
| 1500 – 1750 | 2 |
1. Empirical Relationship — Find Mode
Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is:
The mean and median of a data are 43 and 43.4 respectively. The mode of the distribution is:
If the mean and mode of a data are 12 and 21 respectively, then its median is:
4. Step Deviation
While calculating mean, step deviation method was used \[ u=\frac{x-a}{h}. \] If \(\bar{x}=64,\ h=5\) and \(a=62.5\), then the value of \(\bar{u}\) is:
5. Find Mean and Mode
Find the mean and mode of the following distribution:
| Class Interval | 400–450 | 450–500 | 500–550 | 550–600 | 600–650 | 650–700 |
|---|---|---|---|---|---|---|
| Frequency | 15 | 18 | 20 | 23 | 22 | 12 |
Find the mean and mode of the following distribution:
| Class | 0–15 | 15–30 | 30–45 | 45–60 | 60–75 | 75–90 | 90–105 |
|---|---|---|---|---|---|---|---|
| Frequency | 4 | 8 | 11 | 14 | 10 | 7 | 6 |
Find the median and mode of the following distribution:
| Class Interval | 0–15 | 15–30 | 30–45 | 45–60 | 60–75 | 75–90 | 90–105 |
|---|---|---|---|---|---|---|---|
| Frequency | 15 | 10 | 12 | 9 | 8 | 10 | 6 |
The median is 50 and the sum of all frequencies is 90. Find the values of \(p\) and \(q\).
| Class | 20–30 | 30–40 | 40–50 | 50–60 | 60–70 | 70–80 | 80–90 |
|---|---|---|---|---|---|---|---|
| Frequency | \(p\) | 15 | 25 | 20 | \(q\) | 8 | 10 |
If the median is 32.5 and total frequency is 40, find \(x\) and \(y\).
| Class | 0–10 | 10–20 | 20–30 | 30–40 | 40–50 | 50–60 | 60–70 |
|---|---|---|---|---|---|---|---|
| Frequency | \(x\) | 5 | 9 | 12 | \(y\) | 3 | 2 |
The mean is 28 and sum of frequencies is 100. Find \(p\) and \(q\).
| Class Interval | 0–10 | 10–20 | 20–30 | 30–40 | 40–50 | 50–60 |
|---|---|---|---|---|---|---|
| Frequency | 12 | \(p\) | 27 | 20 | \(q\) | 6 |
Mean is 53. Find the missing frequency \(p\), then find the mode.
| Class Interval | 0–20 | 20–40 | 40–60 | 60–80 | 80–100 |
|---|---|---|---|---|---|
| Frequency | 12 | 15 | \(p\) | 28 | 13 |
Compute the median of the following data:
| Mid-value | 115 | 125 | 135 | 145 | 155 | 165 | 175 |
|---|---|---|---|---|---|---|---|
| Frequency | 12 | 15 | 20 | 16 | 10 | 16 | 11 |
Find the median and the mode for the following distribution:
| Score | Number of students |
|---|---|
| 0 and more | 80 |
| 10 and more | 77 |
| 20 and more | 72 |
| 30 and more | 65 |
| 40 and more | 55 |
| 50 and more | 43 |
| 60 and more | 28 |
| 70 and more | 16 |
| 80 and more | 10 |
| 90 and more | 8 |
| 100 and more | 0 |