2, 4, 6, 8
Here n = 4.
Middle values are 2nd and 3rd:
4 and 6
Median =
4 + 62
= 5
✓ Median = 5
13. Cumulative Frequency ⭐⭐⭐⭐⭐
Cumulative frequency is the running total of frequencies.
Class
f
cf
0–10
4
4
10–20
6
10
20–30
8
18
30–40
5
23
🧠 cf banate waqt previous frequency ko next frequency mein
add karte jao.
14. Median of Grouped Data ⭐⭐⭐⭐⭐
Median =
l +
(
N2
− cf
)
f
× h
Where:
l = lower boundary of median class
N = total frequency
cf = cumulative frequency before median class
f = frequency of median class
h = class size
⚠️ Formula mein cf ka matlab median class se pehle wali
cumulative frequency hai — median class ki cf nahi.
✏️ Example
Suppose:
N = 40
Median class:
20–30
and
l = 20, cf = 14, f = 12, h = 10
Then:
Median =
20 +
20 − 14
12
× 10
= 20 + 5 = 25
✓ Median = 25
15. How to Find Median Class
First calculate:
N = Σf
Then calculate:
N/2
The class whose cumulative frequency is just greater than
N/2 is the median class.
✏️ Example
Suppose:
N = 50
Then:
N/2 = 25
If cumulative frequencies are:
10, 18, 29, 40, 50
The first cf greater than 25 is 29.
Therefore, the corresponding class is the
median class.
16. Mode ⭐⭐⭐⭐⭐
Mode is the value that occurs most frequently.
✏️ Example
Data:
3, 5, 5, 7, 8, 5, 9
5 occurs three times.
✓ Mode = 5
🧠 Mode = jo value sabse zyada baar aaye.
17. Mode of Grouped Data ⭐⭐⭐⭐⭐
Mode =
l +
f₁ − f₀
2f₁ − f₀ − f₂
× h
Where:
l = lower boundary of modal class
f₁ = frequency of modal class
f₀ = frequency of class preceding modal class
f₂ = frequency of class succeeding modal class
h = class size
✏️ Example
Suppose:
l = 20, f₁ = 15, f₀ = 8, f₂ = 10, h = 10
Then:
Mode =
20 +
15 − 830 − 8 − 10
× 10
= 20 +
712
× 10
= 20 +
356
≈ 25.83
✓ Mode ≈ 25.83
18. Modal Class
The class having the highest frequency is called the
modal class.
Class
Frequency
0–10
5
10–20
12
20–30
18
30–40
9
✓ Modal class = 20–30
19. Empirical Relationship ⭐⭐⭐⭐⭐
Mode = 3 Median − 2 Mean
or
3 Median = Mode + 2 Mean
✏️ Example
Mean = 20
Median = 22
Then:
Mode = 3(22) − 2(20)
= 66 − 40
= 26
✓ Mode = 26
⚠️ Is relation ko tabhi use karo jab question/data situation
appropriate ho aur required relationship expected ho.
20. Mean, Median & Mode — Difference
Measure
Basic Idea
Mean
Average value
Median
Middle value
Mode
Most frequent value
🧠 Yaad rakhne ka easiest way:
Mean → Average Median → Middle Mode → Most repeated
21. Graphical Representation
Data can be represented visually using graphs.
For cumulative frequency distributions, the important graph
is the ogive.
Less-than Ogive
Uses upper class boundaries and corresponding less-than
cumulative frequencies.
More-than Ogive
Uses lower class boundaries and corresponding more-than
cumulative frequencies.
22. Less-than Ogive 📈
For a less-than cumulative frequency curve:
X-axis → upper class boundaries
Y-axis → less-than cumulative frequencies
💡 Less-than ogive mein points generally upper boundaries
ke against cumulative frequencies par plot hote hain.
23. More-than Ogive 📉
For a more-than cumulative frequency curve:
X-axis → lower class boundaries
Y-axis → more-than cumulative frequencies
24. Finding Median using Ogives
If less-than and more-than ogives are drawn on the same graph,
their point of intersection gives the median when projected
appropriately onto the x-axis.
🧠 Dono ogive ko same graph par draw karo.
Intersection point se x-axis par perpendicular drop karke
median obtain kiya ja sakta hai.
📌 Graph question mein:
1. Correct cumulative frequency table banao.
2. Correct boundaries use karo.
3. Scale clearly mark karo.
4. Points accurately plot karo.
5. Smooth curve draw karo.
25. Missing Frequency ⭐⭐⭐⭐⭐
In some questions, one frequency is unknown.
Let the missing frequency be x.
Then use the given condition such as mean/median/mode to form
an equation and solve x.
✏️ Example — Mean Based
Suppose total frequency is:
10 + x
and:
Σfx = 200 + 20x
If mean = 15:
15 =
200 + 20x10 + x
Cross multiply:
150 + 15x = 200 + 20x
−50 = 5x
x = −10
⚠️ Negative frequency is impossible, so these assumed values
would not represent a valid frequency question.
💡 Real exam question mein values aisi hongi ki frequency
non-negative integer aaye. Calculation ke end mein
frequency ko logically verify karna zaroori hai.
26. Choosing the Correct Formula
Question asks
Use
Average of data
Mean
Middle value
Median
Most frequent value
Mode
Grouped mean
ΣfxΣf
Grouped median
l +
(N/2 − cf)
f
h
Grouped mode
l +
f₁−f₀2f₁−f₀−f₂
h
27. Most Important Symbols
Symbol
Meaning
x
Observation / class mark
f
Frequency
Σf = N
Total frequency
cf
Cumulative frequency
l
Lower boundary of relevant class
h
Class size
f₀
Frequency before modal class
f₁
Frequency of modal class
f₂
Frequency after modal class
A
Assumed mean
28. Common Exam Mistakes ⚠️
❌ Data ko arrange kiye bina median find karna.
❌ Class mark incorrectly calculate karna.
❌ Σf ko total frequency na lena.
❌ Median formula mein wrong cf use karna.
❌ Modal class ko lowest frequency se select karna.
❌ f₀, f₁, f₂ ko wrong classes se lena.
❌ Ogive mein wrong class boundaries use karna.
❌ Graph ka scale mention na karna.
❌ Arithmetic calculation ke baad answer verify na karna.
29. One-Page Formula Revision ⭐⭐⭐⭐⭐
Mean =
Σxn
Mean =
ΣfxΣf
Mean =
A +
ΣfdΣf
Mean =
A +
h
ΣfuΣf
Median =
l +
(N/2 − cf)
f
h
Mode =
l +
f₁ − f₀
2f₁ − f₀ − f₂
h
Mode = 3 Median − 2 Mean
30. Exam Attack Plan 🎯
STEP 1: Read the complete table.
STEP 2: Identify what is being asked:
Mean / Median / Mode / Graph.
STEP 3: Calculate total frequency N.
STEP 4: Make class marks or cumulative frequencies
as required.
STEP 5: Select the correct formula.
STEP 6: Substitute carefully.
STEP 7: Check the final answer.
STEP 8: For graph questions, check scale and plotting.